incorrect results from bwconncomp
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Erin Linebarger
el 14 de Feb. de 2019
Comentada: Image Analyst
el 16 de Feb. de 2019
I would like to understand how to correctly use the bwconncomp function, as the results I get do not make sense. Here is my problem. I have a binary image of edges like so:

It has been preprocessed to remove all vertices. I want to identify all the edges individually, so I ran the code:
CC1 = bwconncomp(E1);
It says there are only 13 objects, which looks highly suspect, so I pull up the first object like this:
%create cell array of edge matrices
numPixels1 = length(CC1.PixelIdxList);
edges1 = cell(num_1,1);
for ii = 1:num_1
pix = CC1.PixelIdxList{ii};
[rows,cols] = ind2sub(size(E1),pix);
r = max(rows)-min(rows)+1;
c = max(cols)-min(cols)+1;
mat = zeros(r,c);
rows = rows - min(rows)+1;
cols = cols - min(cols)+1;
inds = sub2ind([r,c],rows,cols);
mat(inds) = 1;
edges1{ii} = mat;
end
%show first element
figure;imshow(edges1{1})
And I get this:

I don't understand how counting connected components would actually connect those components before counting, it seems precisely in oppposition to the goal. Please help to clarify the use of this function.
3 comentarios
Respuesta aceptada
Image Analyst
el 16 de Feb. de 2019
Identify the branchpoints with bwmorph() then mask them out.
bpImage = bwmorph(mask, 'branchpoints'); % Find branchpoints in your binary image called "mask"
mask(bpImage) = false; % Erase those branchpoints.
2 comentarios
Image Analyst
el 16 de Feb. de 2019
Yes, while logical variables CAN be treated as numbers 0 and 1, it's always best to use logical operations to avoid the problem you saw. Subtracting a true (1) from a false (0) will require them to be cast to double instead of logical so it can handle the -1. Then that causes weird side effects like you saw, along with not being able to use the array as a logical index anymore (like I did). So while in some circumstances you can use mathemetical operations, it's always safest to stick with logical operations when dealing with logical variables.
Thanks for accepting the answer.
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