Hi , I make spectral analysis for female voice ( wav file for 2 word only ) , I get frequency contents below 1000 Hz , so is this correct , also I suspect computation of power of abs(fft) , please advise , thanks
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Mohamad
el 30 de Mzo. de 2019
Comentada: Image Analyst
el 29 de Dic. de 2020
file1='Left_2_f.wav';
[y,fs] = audioread(file1);
L=length(y);
t=(1000*(0:1/fs:(L-1)/fs))';
n = 2^nextpow2(L);
Y=fft(y,n);
P = abs(Y/n);
P = P(1:n/2+1);
P(2:end-1) = 2*P(2:end-1);
power = abs(Y).^2/n; % power of the DFT
power = power(1:n/2+1);
power(2:end-1) = 2*power(2:end-1);
f = fs*(0:(n/2))/n;
f1 = fs*(0:n-1)/n;
figure
subplot(4,1,1)
plot(t,y)
xlabel('Time in mseconds');
ylabel('Audio Level');
title('Plot of female voice ');
grid on
grid minor
subplot(4,1,2)
plot(f,P)
title('Single-Sided Magnitude Spectrum of female voice ')
xlabel('f (Hz)')
ylabel('Magnitude')
grid on
grid minor
subplot(4,1,3)
[pk,j] = findpeaks(P,'SortStr','descend','NPeaks',8);
Peaks(:,j) = f(j);
xx=(f(:,j));
xx=(sort(xx));
[~,loc] = max(P);
plot(f(1:10*loc),P(1:10*loc),f(j),pk,'o')
title(['The maixmum of Magnitude Spectrum occurs at ( ' ,num2str(xx) , ' ) Hz' ])
xlabel('f (Hz)')
ylabel('Magnitude')
grid on
grid minor
subplot(4,1,4)
plot(f,power)
xlabel('Frequency')
ylabel('Power')
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Respuesta aceptada
Image Analyst
el 30 de Mzo. de 2019
It's correct - females can have audio power below 1 kHz.
To get power, try pwelch() or bandpower().
2 comentarios
Yasir Muhammad
el 29 de Dic. de 2020
would uu tell me how to read all audio files and then ploting fft and maximum spectrum
Image Analyst
el 29 de Dic. de 2020
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