# counting no .of temperature less than 32 in array

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Abhishek singh on 3 Apr 2019
Edited: madhan ravi on 15 Sep 2019
function numfreeze = freezing(v)
count = 0;
i =v()
j = 32
if i < 32
count = count+1
numfreeze = count
else
end

#### 1 Comment

Abhishek singh on 3 Apr 2019
geeting errror
i =
45 21 32 31 51 12
j =
32
Output argument "numfreeze" (and maybe others) not assigned during call to "freezing".

Ngei Katumo on 22 Aug 2019
function w = freezing (A)
w = sum (logical (A(A<32)));
end

madhan ravi on 3 Apr 2019
v=[45 21 32 31 51 12];
threshold=32;
numfreeze = freezing(v,threshold) % function call
function numfreeze = freezing(v,threshold) % function definition
numfreeze = nnz(v<threshold);
end

madhan ravi on 3 Apr 2019
edit: After the comment from sir Image Analyst
You should save the function in a separate file named freezing.m. "Getting error" is useless, paste the full error message that you’re getting (everything in red).
Image Analyst on 11 Jun 2019
You mean freezing.m, since that's what was asked.
madhan ravi on 15 Sep 2019
Ah yes exactly:)

Nazneen Sayyad on 10 Jun 2019
Write a function called freezing that takes a vector of numbers that correspond to daily low temperatures in Fahrenheit. Return numfreeze, the number of days with sub freezing temperatures (that is, lower than 32 F) without using loops. Here is an example run:
numfreeze = freezing([45 21 32 31 51 12])
numfreeze =
3
function numfreeze = freezing(A)
B=A(A<32);
numfreeze=numel(B);
end

Ajith Thomas on 19 Jul 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
no_logical_values=lowerthan_32(lowerthan_32>=0);
numfreeze=length(no_logical_values);
end

#### 1 Comment

Ajith Thomas on 19 Jul 2019
function numfreeze=freezing(w)
lowerthan_32=w(w<32);
numfreeze=numel(lowerthan_32);
end

Roshan Singh on 15 Sep 2019
function numfreeze = freezing(x)
f = x(x<32);
numfreeze = length(f);
end