While loop is continuous.

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jack bennet
jack bennet on 28 Aug 2012
Im trying to write a homeloan function that calcs certain values(deposit, interest etc) and displays an error message if the deposit is less that %20 of the house price.
Only problem is, the function loops continuosly. Any idea how to fix this?? My SCRIPT is below. cheers
function [monthlyPayment, interest] = homeloan(price, deposit, intRate, lengthOfLoan)
% for deposit while using a while loop
deposit <= ((300000)/ 5);
while deposit < 300000
disp('error');
deposit= ((300000)/ 5); % do not forget to do this, otherwise we would loop forever
%monthly payment
monthlyPayment = (((price - deposit)*intRate)*((1 + intRate)^lengthOfLoan))/(((1 + intRate)^lengthOfLoan) - 1)
% interest
interest = (monthlyPayment * lengthOfLoan) - ( price - deposit)
end
  1 Comment
Azzi Abdelmalek
Azzi Abdelmalek on 28 Aug 2012
Edited: Azzi Abdelmalek on 28 Aug 2012
deposit= ((300000)/ 5); % if you do this, you will loop forever
can you post the full code

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Answers (3)

Walter Roberson
Walter Roberson on 28 Aug 2012
deposit <= ((300000)/ 5);
is a logical test, followed by throwing away the result. It is not an assignment.

Arthur
Arthur on 28 Aug 2012
You're not changing the value of deposit in the loop, but always setting it at 300000/5. So deposit is always smaller than 300000, and the loop will run forever.

Image Analyst
Image Analyst on 28 Aug 2012
Try this. Just check to see if the deposit is big enough and warn user if it's not:
function [monthlyPayment, interest] = homeloan(price, deposit, intRate, lengthOfLoan)
monthlyPayment = [];
interest = [];
minDeposit = price * 0.2;
if deposit < minDeposit
warningMessage = sprintf('Error: your deposit of %.2f is less than the required deposit of %.2f, which is 20%%of %.2f',...
deposit, minDeposit, price);
uiwait(warndlg(warningMessage));
else
% Calculate monthly payment
monthlyPayment = (((price - deposit)*intRate)*((1 + intRate)^lengthOfLoan))/(((1 + intRate)^lengthOfLoan) - 1)
% Calculate interest
interest = (monthlyPayment * lengthOfLoan) - ( price - deposit)
end

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