# why im not able plot graph in 1 sec window of 16 sample

2 views (last 30 days)
germanbrain common on 25 Aug 2019
Commented: Image Analyst on 27 Aug 2019
clc;clear all; close all;
A=1;
x=0:0.1:1;
sample=16;
y=A*sin((2*pi./sample)*x)
figure
plot(x,y) Show 1 older comment
germanbrain common on 25 Aug 2019
In one sec window i have to plot sine wave with 16 points.
dpb on 25 Aug 2019
x=linspace(0,1,16);
y=A*sin(2*pi*x);
plot(x,y)
germanbrain common on 27 Aug 2019
thnak you

Image Analyst on 25 Aug 2019
You didn't have anough points to see the sine wave so all you see is a traingle wave. Increase the number of points and use linspace():
numPoints = 50; % Whatever
Amplitude = 1;
t = linspace(0, 1, numPoints);
period = 0.4; % Seconds -- whatever you want;
y = Amplitude * sin((2*pi./period) * t)
plot(t, y, 'bo-', 'LineWidth', 2, 'MarkerSize', 9)
grid on;
xlabel('Time', 'FontSize', 13);
ylabel('Y', 'FontSize', 13);
title('Sine Wave', 'FontSize', 13); germanbrain common on 27 Aug 2019
thank you, but one question i am having here here my input signal is 1 sec or 1hz fre and what about sampling frequnecy here??
Fs is how much?
PS: I need one full cycle in 1 second,in your plot i can se 2.5 cycle.
KALYAN ACHARJYA on 27 Aug 2019
Change the period value, and see the results.
Image Analyst on 27 Aug 2019
fs (omega) is (2*pi/period). For a 1 second, 1Hz chunk of signal, you'll have one wave of the sine wave. You can pick whatever sampling rate you want. Of course the higher it is, the more accurately you'll draw the signal.