generate unit vectors based on matrix size

function [] = lanczos(A, m)

A = readmatrix('output1.txt','Whitespace',' []');

[n,k] = size(A);

V = zeros(k,k);

%V(:,2) = rand(k,1);

V(:,2)=[1 0 0 0 0 0 0 0 0 0 0]';

the v(:,2) is assigned based on matrix size ,which i did manually.But i need it to be created automaticaly based on matrix size.

for suppose if matrix is of size 5*5 then V(:,2)=[1 0 0 0 0]

if matrix is of size 7*7 then V(:,2)=[1 0 0 0 0 0 0]

if matrix is of size 100*100 then V(:,2)=[1 0 0 0 0........] i can't hand write such long vector so i need it to be generated automaticaly based on matrix size.

Answer 1

[James Tursa]

Why not just V(1,2) = 1;

Or if you really need to explicitly set those 0’s then start with V(:,2) = 0; followed by the above.

[Nitish Reddy Kotkur]

v =

0 1

this is the output i got when i used ,v(:,2)=0 followed by V(1,2)=1

[Steven Lord]

The variables v (lower-case) and V (upper-case) are two different variables.

v = 'abracadabra';
V = 1:5;
whos

In the example above whos shows that v and V have different sizes, bytes, and classes.

[Nitish Reddy Kotkur]

and how do i make a transpose of it.