math equation using function
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Roger Nadal on 24 Nov 2019
Commented: Image Analyst on 26 Nov 2019
function will recive input Value a and it caluclate its approximate value to e. e=1/e~~(1-1/n)^n. e value that the difference between the approximation and the actual value of e is smaller than err.function should return the corresponding value of n.
Image Analyst on 24 Nov 2019
I don't know what that means. Let's say that a=8, and e=2.718281828. Do you simply want to return an ouput = (exp(1) - a)??? And do you just want to do a while loop, incrementing the value of n, until (1-1/n)^n is less than 1/e ???
e1 = 1 / exp(1)
while difference > e1
difference = abs(e1 - (1-1/n)^n);
n = n + 1;
n = n - 1; % Undo last addition before the break.
Image Analyst on 26 Nov 2019
Well, only Walter here has the Mind Reading Toolbox, not me, so let's see what code you have so far, if you still want/need help. What modifications did you make to the snippet I gave you?
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