Problem using the FIND function to identify the position of a negative decimal number.
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Stanislao Pinzón
el 28 de Dic. de 2019
Respondida: Image Analyst
el 28 de Dic. de 2019
Hello.
I need to find the position of a negative decimal number in a vector. The code I've used is as follows:
a = -2:0.05:0;
num = -0.95;
position = find(a==-0.95);
The problem is with some numbers like the one set in num. Although the number exists within the a vector, the result I get is:
1-0 empty double row vector
What could be the problem? and how can I fix it?. Thanks.
Best regards
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Respuesta aceptada
Matt J
el 28 de Dic. de 2019
Editada: Matt J
el 28 de Dic. de 2019
The numbers you are comparing differ by small floating point errors,
>> a(22)-(-0.95)
ans =
-1.1102e-16
Use ismembertol, instead.
>> [~,position]=ismembertol(num,a)
position =
22
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