How can I convert 2 column matrix to a cell array?

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Jay Vaidya
Jay Vaidya el 30 de Dic. de 2019
Editada: Jay Vaidya el 1 de En. de 2020
Is there a convenient way to convert a 2 column matrix into a cell array (without using nested for loops if possible)?
The matrix looks like:
Can I make a matrix from the above matrix such that the rows and columns of the new matrix(or a cell array you can say) will be like you see below:
3.JPGthe empty cells can be NAN and the filled cells are the values of the 3rd column of the old matrix.

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Walter Roberson
Walter Roberson el 30 de Dic. de 2019
result = accumarray(matrix(:,[2 1]), matrix(:,3), [], @(v) {v}, {nan})
However I wonder if you would be better off using
result = sparse(matrix(:,2), matrix(:,1), matrix(:,3))
which would be a sparse numeric array instead of a cell array that takes up about 108 bytes per entry.
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Jay Vaidya
Jay Vaidya el 1 de En. de 2020
Editada: Jay Vaidya el 1 de En. de 2020
That is what I am confused as well. If the input matrix(:,1:2) is of the order of mx2. I want to make a graph from this matrix. Lets say the order of the graph (look below) is pxq. Then, the order of the the result matrix should be pxq as well. In other words, I want to transform,
matrix->graph->adjacency matrix-> heatmap. My ultimate goal is to plot a heatmap from the input matrix. Mr. Bobrov, I have made a different thread for this, it would be great if you can help.

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Más respuestas (2)

Jay Vaidya
Jay Vaidya el 31 de Dic. de 2019
Hello Mr. Roberson and Mr. Bobrov,
I am getting an error while running that. I have attached the snapshots of the error that says that SUBS must contain positive integer subscripts(associated with accumarray command) and another one that has an index value problem (associated with the sparse command). For convenience, I have attached the matrix.xlsx file that has the 'matrix' that is being used in this problem.
Attachment: matrix.xlsx (see below)

Andrei Bobrov
Andrei Bobrov el 31 de Dic. de 2019
T = readtable('path\to\your\xls\file\matrix.xlsx','ReadVariableNames',0);
T.Var3 = str2double(T.Var3);
T = T(any(T{:,1:2} ~= 0,2),:);
M = T{:,:};
[i,g] = findgroups(M(:,2));
out = flip(accumarray([M(:,1),i],M(:,3)),1);
  3 comentarios
Jay Vaidya
Jay Vaidya el 31 de Dic. de 2019
So, the out matrix is of the order of 2550x2550. Where the graph is a 51(rows)x51(column) graph. Please see the image below. I want an 'out' matrix which has dimensions of 51x51 and represents just weights. In other words, the 'out' matrix will exactly the same as the graph in figure b.

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