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The code below works to count the letters in each state name:
stateNames = {...
'Alabama'
'Alaska'
'Arizona'
'Arkansas'
'California'
'Colorado'
'Connecticut'
'Delaware'
'Florida'
'Georgia'
'Hawaii'
'Idaho'
'Illinois'
'Indiana'
'Iowa'
'Kansas'
'Kentucky'
'Louisiana'
'Maine'
'Maryland'
'Massachusetts'
'Michigan'
'Minnesota'
'Mississippi'
'Missouri'
'Montana'
'Nebraska'
'Nevada'
'New Hampshire'
'New Jersey'
'New Mexico'
'New York'
'North Carolina'
'North Dakota'
'Ohio'
'Oklahoma'
'Oregon'
'Pennsylvania'
'Rhode Island'
'South Carolina'
'South Dakota'
'Tennessee'
'Texas'
'Utah'
'Vermont'
'Virginia'
'Washington'
'West Virginia'
'Wisconsin'
'Wyoming'}
numStates = length(stateNames)
containsAZ = zeros(numStates, 26);
letters = 'A' : 'Z'
for k = 1 : numStates
% Get the upper case version of this state.
thisState = upper(stateNames{k});
% Count how many times that letter occurs in it.
for c = 1 : length(letters)
thisLetter = letters(c);
containsAZ(k, c) = sum(thisState == thisLetter);
end
% For fun, print out how many characters are in the state name.
for col = 1 : length(letters)
thisCount = containsAZ(k, col);
if thisCount > 0
fprintf('%s contains %d instances of the letter "%c".\n', ...
thisState, thisCount, letters(col));
end
end
end
% Show in command window the counts for each letter.
% Each row is a state name.
containsAZ
% If you want a binary matrix like true or false for whether that letter
% is in the name, rather than a count, just threshold it:
logicalContainsAZ = containsAZ > 0
