[Max,index]=max(array,[ ],2)..... Iam using this syntax to find the maximum value of every column but in case of two equal maximum values it returns the first one... how can I solve this?! Thanks

5 comentarios

Walter Roberson
Walter Roberson el 10 de Feb. de 2020
You have not defined what outcome you would prefer.
Steven Lord
Steven Lord el 10 de Feb. de 2020
That sounds like it's working as it should. From the documentation "If the largest element occurs more than once, then I contains the index to the first occurrence of the value."
What did you expect it to do instead?
Marco Nashaat
Marco Nashaat el 10 de Feb. de 2020
sorry for your trouble....but the problem I'm working on is to find the saddle points of a matrix and now I'm trying this ...
[row,col]=size(matrix);
for I=1:row
for j=1:col
if matrix (I,j)==max(matrix, I)&&matrix (I,j)==min(matrix, j)
indices=[i j;]:
else
indices=[ ]
end
end
end
would it work ...and I could use some help with the syntax!!
Mohymen Kushal
Mohymen Kushal el 26 de Oct. de 2020
if A is a matrix, then max(A,[ ],2) is a column vector containing the maximum value of each row . What is this '2' for ? can anybody explain please. Thanks.
the cyclist
the cyclist el 29 de Oct. de 2020
As clearly stated in the documentation for max, that "2" indicates the matrix dimension along which to take the maximum.

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the cyclist
the cyclist el 10 de Feb. de 2020

0 votos

This code will return the row and column indices where the entry is equal to the column's maximum.
[rowIdx,colIdx] = find(A==max(A))

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