Sum and Difference across row and column
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Muhammad Usman
el 8 de Mayo de 2020
Respondida: Steven Lord
el 8 de Mayo de 2020
Let say there is square matrix of order n-by-n, and n is odd integer
A = rand(3)
A =
0.4218 0.9595 0.8491
0.9157 0.6557 0.9340
0.7922 0.0357 0.6787
I want to add the entries of second column and take difference of entries in second row to the middle number, i.e.
0.6557+0.9595+0.0357-0.9157-0.9340 = -0.1988
How can I do?
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Respuesta aceptada
Stephen23
el 8 de Mayo de 2020
>> sum(A(:,2))-A(2,1)-A(2,3)
ans = -0.19880
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Steven Lord
el 8 de Mayo de 2020
You can do this with two simple sum calls and two basic arithmetic operations if you use the inclusion-exclusion principle. Since this sounds like it may be a homework assignment I'm not going to give the complete answer.
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