Roundation In Binary Problem

Hello everyone, I need a programme help. I think it will be obvious if I will examine it with an example.

Consider we have a matrix (6x6) in binary;

       0     0     1     0     1     0
       0     1     1     0     1     1
y=     1     0     0     0     1     0
       0     1     0     1     1     0
       0     0     0     1     0     1
       0     0     0     0     0     1

I would like to make roundation. Means it will look the rows' one by one, if the last number is 1, it will add 1 to the number (in binary) and in the end it will return matrix 5x5 (for this example).

For this example:

       0     0     1     0     1     
       0     1     1     1     0     
y=     1     0     0     0     1     
       0     1     0     1     1     
       0     0     0     1     1     
       0     0     0     0     1

And it should do it for any matrix which is (nxn)

Thanks from now ;)

[Walter Roberson]

What code have you tried?

[Image Analyst]

I don't understand. I've never heard of "roundation". What does "Add 1 to the number in binary" mean? If it's binary (logical) adding 1 will still leave it at 1 - it will get clipped. And how does doing that chop off the last column?

Answer 1

[Matt J]

 out = dec2bin( y(:,1:end-1)*2.^((n-2:-1:0).') + y(:,end) )-'0';

[Turgut]

thank you so much it works perfect ;)