fitting an ellipse to my binary iris image ?

I want to fit an ellipse to the boundary of the iris in my edge map eye image in order to segment the iris from the background.i really appretiate your help. the image is :
thanks inadvance.
na

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Matt J
Matt J el 12 de Nov. de 2012
function report=ellipsefit(XY)
%ELLIPSEFIT - form 2D ellipse fit to given x,y data
%
% report=ellipsefit(XY)
%
%in:
%
% XY: Input matrix of 2D coordinates to be fit. Each column XY(:,i) is [xi;yi]
%
%out: Finds the ellipse fitting the input data parametrized both as
% A*x^2+B*x*y C*y^2+D*x+E*y=1 and [x-x0,y-y0]*Q*[x-x0;y-y0]=1
%
% report: a structure output with the following fields
%
% report.Q: the matrix Q
% report.d: the vector [x0,y0]
% report.ABCDE: the vector [A,B,C,D,E]
% report.AxesDiams: The minor and major ellipse diameters
% report.theta: The counter-clockwise rotation of the ellipse.
%
%NOTE: The code will give errors if the data fit traces out a non-elliptic or
% degenerate conic section.
%
%See also ellipsoidfit
X=XY(1,:).';
Y=XY(2,:).';
M= [X.^2, X.*Y, Y.^2, X, Y, -ones(size(X,1),1)];
[U,S,V]=svd(M,0);
ABCDEF=V(:,end);
if size(ABCDEF,2)>1
error 'Data cannot be fit with unique ellipse'
else
ABCDEF=num2cell(ABCDEF);
end
[A,B,C,D,E,F]=deal(ABCDEF{:});
Q=[A, B/2;B/2 C];
x0=-Q\[D;E]/2;
dd=F+x0'*Q*x0;
Q=Q/dd;
[R,eigen]=eig(Q);
eigen=eigen([1,4]);
if ~all(eigen>=0), error 'Fit produced a non-elliptic conic section'; end
idx=eigen>0;
eigen(idx)=1./eigen(idx);
AxesDiams = 2*sqrt(eigen);
theta=atand(tand(-atan2(R(1),R(2))*180/pi));
report.Q=Q;
report.d=x0(:).';
report.ABCDE=[A, B, C, D, E]/F;
report.AxesDiams=sort(AxesDiams(:)).';
report.theta=theta;

13 comentarios

nedaa
nedaa el 12 de Nov. de 2012
thank you for your answer, but please what is the input parameters (XY)??
Matt J
Matt J el 12 de Nov. de 2012
The sample x,y coordinates to which you are trying to fit the ellipse.
Matt J
Matt J el 27 de Feb. de 2013
Sure. Once you obtain the boundary xy coordinates.
leon
leon el 28 de Feb. de 2013
Matt J,
Can you use the mango picture, do a example to me to see because i am begginer, i no understand how to obtain the boundary xy coordinates.
Matt J
Matt J el 28 de Feb. de 2013
Editada: Matt J el 28 de Feb. de 2013
That appears to be very challenging! In any case, it's not relevant to this thread or my code, which is about ellipse fitting. It's more of a segmentation problem.
leon
leon el 20 de Mzo. de 2013
Image Analyst
Image Analyst el 20 de Mzo. de 2013
First get rid of the clutter by extracting just the largest object. Then call bwboundaries() to get the perimeter coordinates. Then use the ellipsefit() code.
leon
leon el 26 de Mzo. de 2013
Image Analyst ,
call bwboundaries like this http://snag.gy/gxOak.jpg ?
Image Analyst
Image Analyst el 26 de Mzo. de 2013
Well I can't tell from that image if you called bwboundaries() or not, but what I can tell is that you didn't extract the largest blob into it's own image. That is probably a separate topic, more general purpose than this, and probably should be a separate, new question because lots of people might benefit from it. So, ask a new question like "How can I extract the largest blob in a binary image?"
leon
leon el 28 de Mzo. de 2013
Matt J,
how to read the image i want using your code or other code because i try to run but cannot read the image. Like below
imread("abc.jpg") a= imread("abc.jpg") imshow(a)
already run like the top code but cannot read the image. i want ask got other code to read the image?
Matt J
Matt J el 28 de Mzo. de 2013
Matt J, how to read the image i want using your code
You were probably really talking to ImageAnalyst.
Image Analyst
Image Analyst el 31 de Oct. de 2016
Except that I didn't post any code.

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