substracting every row from each other
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Selma Nur Keskin
el 6 de Jun. de 2020
Comentada: Selma Nur Keskin
el 7 de Jun. de 2020
I am trying to substract every other row using 2 loops, what is wrong with this code?
Here is the code,
% these are the coordinates I am using
coor=[x' y' z'];
%number of the rows is my atomnumber
atomnum=size(x,2);
contactmapdistance=zeros;
for i=atomnum : 1
for j= 1:atomnum
contactmapdistance(i,3)=coor(i,:) - coor(j,:);
i=i-1;
end
j=j+1;
end
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Image Analyst
el 6 de Jun. de 2020
Editada: Image Analyst
el 6 de Jun. de 2020
Do you mean like this:
% Initialize data
% numRows = 5
x = randi(9, numRows, 1);
y = randi(9, numRows, 1);
z = randi(9, numRows, 1);
% These are the coordinates I am using
coor = [x(:), y(:), z(:)]
% number of the rows is my atomnumber
% atomnum = size(x, 2)
contactMapDistance = zeros(ceil(numRows/2) - 1, 3);
% Subtract row 1 from row 3, row 3 from row 5, row 5 from row 7, etc.
cRow = 1;
for row = 1 : 2 : numRows - 2
contactMapDistance(cRow, :) = coor(row+2, :) - coor(row, :);
cRow = cRow + 1;
end
contactMapDistance % Show in command window
4 comentarios
Image Analyst
el 6 de Jun. de 2020
Like this:
coor = [x(:), y(:), z(:)]
contactMapDistance = coor(1, :) - coor
Note that the way I set up coor is better than your way because my way can handle it no matter if x, y, and z are row vectors or column vectors, which is not true if you use the ' like you did.
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