how can i check if n2 is a sub number of n1? (HW qst.)

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for ex.:
n1 = 123; n2 = 12; (n1>=n2)
n2 is a sub number of n1
i can't make any use of strings or arrays
  7 Comments
Azzi Abdelmalek
Azzi Abdelmalek on 4 Jan 2013
Edited: Azzi Abdelmalek on 4 Jan 2013
check this
2345-fix(2345/10^3)*10^3
then
345-fix(345/10^2)*10^2
and so on

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Accepted Answer

Sean de Wolski
Sean de Wolski on 4 Jan 2013
Here is a hint:
a = 131245;
b = 12;
op = @(x)hidden_for_you_to_figure_out(x);
pa = op(a);
pb = op(b);
isASub = false; %guilty until proven innocent
for ii = pb:pa
amii = mod(a,(10^ii));
if amii == b
isASub = true;
return;
else
for jj = 1:(ii-pb)
afjj = floor(amii./(10^jj));
if b == afjj
isASub = true;
return;
end
end
end
end
All you have to do it figure out the contents of op().
  1 Comment
Zaza
Zaza on 6 Jan 2013
Edited: Zaza on 6 Jan 2013
op() == num_of_digits() ???

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More Answers (2)

Azzi Abdelmalek
Azzi Abdelmalek on 4 Jan 2013
Edited: Azzi Abdelmalek on 4 Jan 2013
n1=12456;
n2=245
a=num2str(n1);
b=num2str(n2);
c=all(ismember(b,a))
if c is equal to 1 that means n2 is a sub number of n1
  6 Comments

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Walter Roberson
Walter Roberson on 4 Jan 2013
Create a function that calculates the decimal expansion of a number in reverse order. mod() 10 gives the next digit to be output, integer division by 10, if the result is non-zero keep going.
Apply that to both numbers.
Now match the reversed n2 to the reversed n1.

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