# How to put for loop outcome into 1 column in right order

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daarneokyddam on 26 Oct 2020
Commented: daarneokyddam on 26 Oct 2020
Hi guys, I made the following for loop where I calculated the response errors for each target. Now instead of putting them in a new matrix in 4 different columns, I want to put the error responses (err) as 1 column in the old matrix (res), in the correct order (so each error response matches its trials). Can somebody explain how to do this?
res = S.res;
trials = res(:,1);
targets = res(:,7);
responses = res(:,8);
oria = [3,4,5,6];
tar = [1,2,3,4];
num = numel(oria);
out = cell(1,num);
for k = 1:num
tarsel = targets==tar(k);
resp = responses(tarsel);
orib = res(tarsel,oria(k));
err = resp - orib;
err(err<-90) = err(err<-90)+180;
err(err>90) = err(err>90)-180;
out{k} = err;
end
out = [out{:}];

Image Analyst on 26 Oct 2020
Edited: Image Analyst on 26 Oct 2020
Can't you just say
res(:, 1) = err(:);
inside the loop? But every iteration will overwrite column 1 of course so not sure why, or if, you want that.
If that doesn't work, please attach your variables in a .mat file.
daarneokyddam on 26 Oct 2020
No I do not want to overwrite them. I want each response error value to be in the row with its corresponding trial (in column res(:,9)). Because I had to calculate the errors based on 4 different targets, there are 4 different groups and I can't get the response errors to match the correct trial.