How can I shift Right which is an array of numbers?
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Micky
el 14 de Feb. de 2013
Comentada: vishwajit jadhav
el 26 de Jun. de 2020
I need is a new shifted array and eventually I want to add the arrays.(New Shifted array + Original Array). Can I do something like e.g . aa =[11 22 33 44]; bb = aa(2:4); % this is shifting left It gives bb = [22 33 44], but one value is dropped out. If possible can someone provide method to shift right and how to pad the dropped out value appropriately so that the size of the new array remains same as the original array?
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Azzi Abdelmalek
el 14 de Feb. de 2013
Editada: Azzi Abdelmalek
el 14 de Feb. de 2013
use circshift function
circshift(aa,[0 -1])
or
circshift(aa,[0 1])
7 comentarios
Azzi Abdelmalek
el 14 de Feb. de 2013
Editada: Azzi Abdelmalek
el 14 de Feb. de 2013
n=2
x= [11;22;33;44;55;66]
x=circshift(x,[n 0])
x(1:n)=0 % or what you want
Más respuestas (2)
Image Analyst
el 14 de Feb. de 2013
Not quire sure what you're describing about not dropping off any values and having bb be the same size as aa, but how about this:
aa =[11 22 33 44];
bb = zeros(size(aa))
bb(2:4) = aa(2:4)
% or
bb1 = zeros(size(aa))
bb1(1:3) = aa(2:4)
In the command window:
bb =
0 22 33 44
bb1 =
22 33 44 0
You can see there is a zero and no value is dropped off or lost and the size of bb is the same as aa. If one of those methods is not what you want, explain in more detail.
3 comentarios
Image Analyst
el 14 de Feb. de 2013
Editada: Image Analyst
el 14 de Feb. de 2013
My solution will work. You just have to generalize it to "k" instead of fixed numbers of 2:4 like your example.
x = [11;22;33;44;55;66]
% k = -2;
k = +2;
s = zeros(size(x));
if k >= 1
s(k+1:end) = x(1:end-k)
elseif k <= -1
s(1:end+k) = x(-k+1:end)
end
komal
el 14 de Jun. de 2019
Ques= x =[11;22;33;44]
i want this results
x = [0;11;22;33;44]
How can i do it:
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