How do to get a specific time from datetime format in Matlab?
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Kofial
el 11 de Nov. de 2020
Comentada: Kofial
el 12 de Nov. de 2020
I have these data:
x=(17-Apr-2020 06:59:00,17-Apr-2020 07:00:00,17-Apr-2020 07:01:00,17-Apr-2020,07:02:0017-Apr-2020,07:03:00)
y=(06:58:30,17-Apr-2020 06:59:30,17-Apr-2020 07:00:30,17-Apr-2020 07:01:30,17-Apr-2020 07:02:30,17-Apr-2020 07:03:30)
Both times (x,y) are in the datetime format).
To get the time for x from 07:00:00 till the end I do this:
interpolation_time = (x(420):minutes(1):x(end));
For y I need it from 07:00:30 till the end. How can I do it? It has a different timestamp.
Thank you!
Respuesta aceptada
Walter Roberson
el 11 de Nov. de 2020
Editada: Walter Roberson
el 11 de Nov. de 2020
[xh, xm, xs] = hms(x);
xidx = find(xh >= 7 & xm >= 0, 1);
[yh, ym, ys] = hms(y);
yidx = find(yh >= 7 & ym >= 0 & ys >= 30, 1);
selected_x = x(xidx:end);
selected_y = y(yidx:end);
Note here that this code is perfectly happy if the dates do not match at all, and if the entries are out of order. Your problem definition involved finding the first entry that meets a particular time-based criteria that ignores dates.
Perhaps you should use isbetween() ?
See also dateshift() -- for example
xbase = dateshift(x(1), 'start', 'day');
dx = x - xbase;
dy = y - xbase;
maskx = dx >= hours(7);
masky = dy >= hours(7) + seconds(30);
1 comentario
Steven Lord
el 11 de Nov. de 2020
You can compute dx and dy without computing xbase using the timeofday function for datetime arrays.
dt = datetime('now') + hours(48*randn(10, 1)) + minutes(60*randn(10, 1));
td = timeofday(dt);
results = table(dt, td, 'VariableNames', ["Date and time", "Time since midnight"])
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