Please how to calculate the number of 1 and 0 in each position in a binary vector

For example my vector is like this: Vector = 00000001111000000000111111100000000000000011111111

I want to calculate the number of 0 in each position and the number of 1 in each position like 7zeros4ones9zeros7ones.....

Please need help

Answer 1

[Ameer Hamza]

Try this

str = '00000001111000000000111111100000000000000011111111';
x = diff([0 find(diff(str-'0')) numel(str)])

Result

>> x
x =
     7     4     9     7    15     8

[Jonas Madjiri]

Thank you very much Ameer Hamza

Answer 2

[Image Analyst]

I see you've already accepted an answer so I guess this isn't what you wanted, but it's what I thought you wanted:

vec = [0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1];
% Find the lengths of the stretches of 1's.
props = regionprops(logical(vec), 'Area');
numOnes = [props.Area]
% Find the lengths of the stretches of 0's.
props = regionprops(logical(vec==0), 'Area');
numZeroes = [props.Area]

You'll see the lengths of the runs of both 1's and 0's:

numOnes =

4 7 8

numZeroes =

7 9 15

and it gives the number of 1's and 0's to you explicitly without having to know whether the first element is a 0 or 1 if they're interlaced like Ameer's answer.

[Jonas Madjiri]

Thank you Analyste. That's exactly what I wanted.