Delete rows from an array

Good afternoon

I have a long array of numbers, CEC (52560x1) and I would like to delete the rows in the following way:

r = 1:1:8760
t = 0:1:8759
CEC((2+6*t):(6*r))

I tried to set it into a loop by:

for r = 1:1:8760
    for t = 0:1:8759
        CEC((2+6*t):(6*r)) = [];
    end
end

But it is not working for me. Any ideas?

Thank you!

[SHIVAM KUMAR]

Couldn't get how you want to delete in a 1 D array like that .

CEC((2+6*t):(6*r)) = [];

This shall change all locations from 2+6*t to 6* r to empty.

and doing in loop means entire array will become empty except index [1,2]

[Ricardo López]

I want those rows empty, so the result would be an array of the same length with 0 in the desired values.

[Image Analyst]

Please give some actual numbers. For example, what indexes represent the first set of rows to delete, and the second set of rows to delete?

Answer 1

[David Hill]

a=CEC(1:6:52560);
CEC=zeros(size(CEC));
CEC(1:6:52560)=a;

Answer 2

[SHIVAM KUMAR]

Your code will work like this if used on 1 D array .

CEC((2+6):end) = [0];

If you are using that your array shall be 52560X52560.

then you can use

for r = 1:1:8760
    for t = 0:1:8759
        CEC((2+6*t),(6*r)) = [0]; %Use a comma
    end
end

[SHIVAM KUMAR]

ie. only have values for index 1 to 8 and all other indexes will be 0.