# Delete rows from an array

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Ricardo López on 15 Dec 2020
Commented: Image Analyst on 15 Dec 2020
Good afternoon
I have a long array of numbers, CEC (52560x1) and I would like to delete the rows in the following way:
r = 1:1:8760
t = 0:1:8759
CEC((2+6*t):(6*r))
I tried to set it into a loop by:
for r = 1:1:8760
for t = 0:1:8759
CEC((2+6*t):(6*r)) = [];
end
end
But it is not working for me. Any ideas?
Thank you!
Image Analyst on 15 Dec 2020
Please give some actual numbers. For example, what indexes represent the first set of rows to delete, and the second set of rows to delete?

David Hill on 15 Dec 2020
a=CEC(1:6:52560);
CEC=zeros(size(CEC));
CEC(1:6:52560)=a;

SHIVAM KUMAR on 15 Dec 2020
Edited: SHIVAM KUMAR on 15 Dec 2020
Your code will work like this if used on 1 D array .
CEC((2+6):end) = [0];
If you are using that your array shall be 52560X52560.
then you can use
for r = 1:1:8760
for t = 0:1:8759
CEC((2+6*t),(6*r)) = [0]; %Use a comma
end
end
SHIVAM KUMAR on 15 Dec 2020
ie. only have values for index 1 to 8 and all other indexes will be 0.