Help plotting a projectile motion graph
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Michael
el 20 de Abr. de 2013
Comentada: Image Analyst
el 30 de En. de 2021
Hello, I'm trying to plot a projectile motion graph at the given angles using this code.
clear all
angle=[0.4, 0.6, pi/4, 1.0, 1.2];
V0=120;
g=-9.8
t=0:.01:500;
Ax=0;
Ay=g;
x=V0*cos(angle);
y=V0*sin(angle)-9.8*t;
plot(x,y);
I'm a novice when I comes to coding, could someone help me fix this code so that I could plot 5 projectile motion graphs for the 5 given angles
2 comentarios
Shawn Wachter
el 30 de En. de 2021
Perhaps the following line needs correction: y=V0*sin(angle)-9.8*t;.
I think you want to use t**2, as shown here: y=V0*sin(angle)-9.8*t^2;
Hope this helps!
Image Analyst
el 30 de En. de 2021
Yes, that's what I showed him 8 years ago in the Answer section below.
y = yVelocity .* t + (1/2) * Ay .* t.^2;
In the future, you can get credit in terms of reputation points if you post an Answer in the answer section below, but not up here in the comments section which is used to ask posters to clarify their question.
Respuesta aceptada
Image Analyst
el 21 de Abr. de 2013
Close, but you need to have a loop over the angle. Try this. Use a smaller max time if you want to notice the projectile actually going up before it falls.
clc;
clear all
workspace;
format compact;
format long g;
angle = [0.4, 0.6, pi/4, 1.0, 1.2];
V0 = 120;
g = -9.8;
t = 0 : .01 : 500;
Ax = 0;
Ay= g;
numberOfAngles = length(angle);
for k = 1 : numberOfAngles
thisAngle = angle(k);
xVelocity = V0 * cos(thisAngle);
yVelocity = V0 * sin(thisAngle);
x = xVelocity .* t + (1/2) * Ax .* t.^2;
y = yVelocity .* t + (1/2) * Ay .* t.^2;
subplot(2, 3, k);
plot(x, y, 'b-', 'LIneWidth', 3);
caption = sprintf('Angle = %.3f radians = %.2f degrees\n', ...
thisAngle, thisAngle*180/pi);
title(caption, 'FontSize', 15);
grid on;
xlim([0 6e4]);
end
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
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