Loop ,Comparison for each element

2 visualizaciones (últimos 30 días)
Suizwati
Suizwati el 11 de Jul. de 2013
Hello everyone.. I would to ask a question regarding to optimization problem. I have 2 control variable denotes as x1 and x2. The fitness function is y=x1+x2..Value of x1 and x2 will be generate by random. Let say I have this value.. x1=(1,3,4,7,9) , x2=(2,4,6,8,10) , y=( 3,7,10,15,19). I want to compare each elements of y in order to update the new location of x1 and x2 which is y1<y1, y1<y2 & y2<y2 , y1<y3 & y2<y3 & y3<y3 , y1<y4 & y2<y4 & y3<y4 & y4<y4 and y1<y5 & y2<y5 & y3<y5 & y4<y5 & y5<y5. Can anybody help on how to write the algorithm.
tq
  3 comentarios
Suizwati
Suizwati el 12 de Jul. de 2013
i want to compare each value of the fitness. if the conditions is not true. it will maintain the fitness from previous value. Meanwhile if the condition is true it will update the value of x1 and x2 becomes x1_new and x2_new and produce the new fitness.
Image Analyst
Image Analyst el 12 de Jul. de 2013
Editada: Image Analyst el 12 de Jul. de 2013
We still don't understand "the new location of x1 and x2 which is y1<y1, y1<y2 & y2<y2 , y1<y3 & y2<y3 & y3<y3 , y1<y4 & y2<y4 & y3<y4 & y4<y4 and y1<y5 & y2<y5 & y3<y5 & y4<y5 & y5<y5. " First of all, you can never have y1<y1 or y2<y2 or y3<y3 or y4<y4 or y5<y5 so what you are trying to do? Secondly, the new location of x1 and x2 would be a boolean if you are doing all those comparisons. What does it mean that the new location is true or false? The new location must be an index, from 1 to "end" in integer steps, not a boolean.

Iniciar sesión para comentar.

Respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by