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How to shorten the amount of decimals?

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Garrett
Garrett el 20 de Mayo de 2021
Comentada: Steven Lord el 20 de Mayo de 2021
I keep getting really long numerical values as output:
An =
0.024234995896557227359496464702679*alpha
0.15943782393832228295849338860996*alpha
-0.12536421301907562828842055676579*alpha
-0.03553313448766475646513348990721*alpha
-0.13243736773001789371670675334921*alpha
-1.1264101534225156844164497805098*alpha
0.032972016135334102699585911872833*alpha
0.10090249826183501633095025194958*alpha
0.094800519200094255394106279895626*alpha
-0.031355837620080097288391753550103*alpha
How can i reduce this to only a couple decimal places?
Entire code for reference:
clc
clear
N = 19;
AR = 6;
n =1:2:N;
b = 6;
Vinf = 1;
c = 1;
deltay = b./(N+1);
y0n = -(b./2)+n.*deltay;
syms alpha
A = sym('A', [1, N]);
A = A(1:2:end);
Pi = sym(pi);
theta = (linspace((Pi/6),(Pi/2),numel(n)).');
S1 = sum(A.*sin(n.*(theta)));
S2 = sum(n.*A.*(sin(n.*(theta))./sin((theta))));
eq1 = (2*AR/pi)*S1+S2 == alpha;
[A,b] = equationsToMatrix(eq1, A);
x = linsolve (A,b);
An = vpa(x)

Respuesta aceptada

Star Strider
Star Strider el 20 de Mayo de 2021
Use the digits function.
  1 comentario
Steven Lord
Steven Lord el 20 de Mayo de 2021
You can instead call vpa with two inputs if you don't want to affect the number of digits for future calls.

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