datetime conversion lose nanoseconds
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I have converted an array from epoch time in nanoseconds to datetime using the following:
t(i,1)= datetime(B(i,1),'ConvertFrom','epochtime','TicksPerSecond',1e9,'Format','dd-MMM-yyyy HH:mm:ss.SSSSSSSSS');
the coversion is ok but once opened the array somehow the this part SSSSSSSSS is not displayed at all.
At the same time doing it without a function value per value it works...
How can I solve this issue?
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Stephen23
el 21 de Mayo de 2021
ms = intmax('int64');
dt = datetime(ms,'ConvertFrom','epochtime','TicksPerSecond',1e9,'Format','dd-MMM-yyyy HH:mm:ss.SSSSSSSSS')
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Steven Lord
el 21 de Mayo de 2021
What Format did you use when you assigned the datetime in the first row of t? Was it one that did not include the nanosecond information?
format1 = 'yyyy-MM-dd HH';
t = datetime('now', 'Format', format1)
format2 = 'HH-mm-ss ''on'' yyyy-MM-dd';
t(2, 1) = datetime('now', 'Format', format2)
The whole array uses format1 because that was the format already in use when you assigned to the second row of t. The second element of t was converted to use the existing format. If you change the array's Format both elements are displayed in the new format.
t.Format = format2
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