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Animation of image

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John
John el 13 de Jun. de 2011
Comentada: Image Analyst el 2 de Nov. de 2017
Hello, I need some help. I have a project to create animation of an image mooving by some points of two arrays X and Y. This two arrays define some curve. I can put the background image and another one on top of it. But I can't think of a way to animate it. I tried every think I could think of but nothing is satisfactory ednouth. Can some one help me. If you require some code I could provide you. Thank you in advance!

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David Young
David Young el 14 de Jun. de 2011
Here's something simple that works - though it's not elegant or efficient:
% image data
bigIm = imread('street1.jpg');
smallysize = 50;
smallxsize = 70;
smallIm = bigIm(188:188+smallysize-1, 177:177+smallxsize-1, :);
% trajectory data
trajy = 400:-5:100;
trajx = trajy;
% animated display
for step = 1:length(trajx)
displayIm = bigIm;
displayIm(trajy(step):trajy(step)+smallysize-1, ...
trajx(step):trajx(step)+smallxsize-1, :) = smallIm;
imshow(displayIm);
pause(0.2);
end
  2 comentarios
subjoy sahu
subjoy sahu el 2 de Nov. de 2017
How to save this file. I am trying but it came as a figure..plzz help
Image Analyst
Image Analyst el 2 de Nov. de 2017
Call getimage() to extract the image out of the axes on the figure.

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Más respuestas (3)

Arnaud Miege
Arnaud Miege el 13 de Jun. de 2011
Have a look at the Animation section of the MATLAB documentation.
HTH,
Arnaud

Image Analyst
Image Analyst el 13 de Jun. de 2011

John
John el 13 de Jun. de 2011
Well, thank you. I have read this documents. But they are not what I need. I mean I can't make my object to move in the axis to create the animation and this is the problem.I have one image over a background image and I need to moove it by specific coordinates. This is what I can't do. I tried to put the top image in new axis and to move this new axis. Not any luck... Any ideas how I can move my top image over the background?
  2 comentarios
Arnaud Miege
Arnaud Miege el 14 de Jun. de 2011
Can you post your code?
Jonas Reber
Jonas Reber el 15 de Jun. de 2011
yes - could you provide some code, then its much easier to help.

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