Combine hundred of mat files into one mat file (same quantity of row and column)

Hello Sir,

I have 123 mat files with the same quantity of column and row (example in the attachments).

The problem is I want to combine all these 123 mat files into one mat file in order to plot graph.

How can I do?

Thank you for your support.

Answer 1

[Image Analyst]

See the FAQ:

https://matlab.fandom.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F

[Pasu Surananchanok]

Thanks bro

Answer 2

[Voss]

Here's one way:

% file_names = sprintfc('bearing1_1_%d.mat',1:123); % use this for files 1-123
file_names = sprintfc('bearing1_1_%d.mat',1:3);

% load the files into a struct array:
for ii = 1:numel(file_names)
    data(ii) = load(file_names{ii});
end
disp(data)

  1×3 struct array with fields:

    a

% vertically concatenate each struct's 'a' field into 
% the 'a' field of a scalar struct 'all_data':
all_data = struct('a',vertcat(data.a))

all_data = struct with fields:
    a: [98304×2 double]

% plot all the data:
plot(all_data.a(:,1),all_data.a(:,2),'.');

% save the combined data to a mat file:
save('bearing1_1_all.mat','-struct','all_data');
% check the mat file:
S = load('bearing1_1_all.mat')

S = struct with fields:
    a: [98304×2 double]

[Pasu Surananchanok]

Thank you sir

Answer 3

[Ive J]

You can load all together:

files = ["bearing1_1_1.mat", "bearing1_1_2.mat"]; % add all files here, use dir or ls
ds = fileDatastore(files, 'ReadFcn', @(x)struct2array(load(x)));
ds = readall(ds);
ds = vertcat(ds{:});

[Turlough Hughes]

Additionally, a handy way to write the filenames is:

files = "bearing1_1_" + (1:123) + ".mat"

[Pasu Surananchanok]

Thank you Bro. You save my life.