help on graph (w/o common matrix plotting built-in functions)

Dear all,
based on a matrix of zeros and ones, let's say 10 x 365 (10 years a 365 days), I would like to plot a '-' for a one and leave the position blank ' ' for a zero.
Thus, the graph should e.g. look like:
....
------ --- --- ---- ---- ------ ----- --
-------- ------ --------------- -----------
------ -- ---------- --------- ---------
----- --------------- ------ ---------- -
.....
Any hint appreciated.

 Respuesta aceptada

In that case, maybe something like this will get you close.
A = randi(2,10,365)-1;
x = 1:size(A,2);
y = size(A,1):-1:1;
for i = 1:size(A,1)
A(i,:) = A(i,:)*y(i);
end
A(A==0) = NaN;
for i = 1:size(A,1)
line(x, A(i,:), 'Marker', '_', 'linestyle', 'none', 'MarkerSize', 0.1)
end

Más respuestas (5)

A = randi(2,10,365)-1
A = 10×365
1 1 1 1 1 1 1 1 0 1 0 1 1 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 1 0 1 0 0 1 0 1 1 0 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 1 1 1 1 0 0 0 1 1 1 1 0 1 1 0 1 0 1 1 1 1 0 1 1 0 0 0 0 1 1 0 0 0 1 1 1 1 0 0 0 1 0 0 1 0 1 1 1 1 0 1 1 0 0 0 0 1 0 0 0 1 1 1 1 0 0 0 1 0 0 0 0 1 1 0 1 0 0 0 1 1 0 1 1 0 0 0 0 1 1 1 0 0 1 1 1 0 0 0 1 0 0 1 0 1 0 1 1 0 0 1 1 0 0 1 1 1 0 0 0 1 1 0 1 0 1 1 0 1 0 0 1 0 1 0 0 1 0 1 0 0 1 1 0 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1 0 0 1 1 1 1 1 1 1 0 0 1 0 1 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 0 1 0 0 0 0 0 0 1 0 1 1 0 0 1 1 1 1 1 0 0 0 0 0 1 0 0 1 0 0 1 1 1 0 1 1 1 0 0 1 0 1 0 1 0 0 1 0 0 0 1 1 1 0 1 0 0 1
str = repmat(' ', size(A));
str(A==1) = '-';
disp(str)
-------- - -- -- -- -- - - ------ - --- --- -- - - - - - -- --- - --- - -- - -- -- -- --- ---- -- --- ---- - - - - -- - ------- - - - - - ---- --- - -- --- - -- - --- - -- - - - ----- --- ---- ------- - - - - --- - ------- ---- -- -- - - - -- - -- - - - - -- - ---- -- -- - -- --- - - - -- - - -- ----- - - ---- ---- -- - -- ------- --- - - - - --- ---- - - - - - -- - - ---- - - - ------ ------ - --- --- -- -- - - - -- - - -- --- -- - ----- -- - - -- ---- ---- - -- - - - --- - - -- - - -- - -- - - - - - -- -- - --- -- --- - -- - - - --- - -- -- - ---- -- - ---- -- -- --- --- -- -- - - - ----- ---- - - ---- - - ---- - --- - -- --- -- - --- --- ----- -- -- --- - -- - --- - --- - --- --- ------ -- - -- - - ----- - --- ----- -- - - - ------ ---- - - -- --- ----- - - --- -- -- - - ----- - - - - ----- - - - ----- -- - - - - - ---- -- - ---- --- - ------ - - -- - -- ---- - - ---- --- ---- --- - --- - - - - - -- ------ ---- --- - --- - -- ------ --- -- -- - -- -- - ----- --- - - - --------- - - ---- - --- - - -- ----- --- --- - -------- ---- - - ------- -- - - ---- - - -- - - ---- --- - - - - - - -- - -- -- --- --- - -- - -- ---- - - -- - --- -- - - --- --- - - - - - ----- ----- -- - -- -- --- - -- -- - - - ---- - -- --- - -- - -- -- ----- ---------- - ---- -- -- - -- - - - ---- ----- - --- - -- - ------ - ---- -- - - - - - - -- - --- --- -- ---- - - - - - - - - - - - -- -- --- -- - ---- - --- - ---- - - - -- ---- - --- - - - --- - ----- -- ---- ---- - - ----- -- - - - -- - - --- - -- -- - - - --- -- - - -- - -- - - - -- -- - - -- --- - - - - - - - - ---- - -- - ----- - --- - - - - - -- - -- - --- -- - - - - -- --- --- - -- --- -- -- ---- --- - - - - - - -- - - -- - ----------- - - - ------ - - - --- -- - - - --- -- -- - - --- - - -- -- ---- - ---- - -- - ------- - - - - ---- ----- -- ---- - ---- ---- - -- - - - -- - - - - - - --- -- - --- ---- -- ------- -- -- - - - - - - - --- - -- --- --- - - - ----- - -- - -- - - --- ------- - -- -- - -- --- - - -- --- --- -- --- -- ------ -- - --- --- -- - ---- - - -- ---- -- - --- - -- - - - --- -- --------- -- - --- - - - --- - ---- -- - - --- - - -- ----- - - -- - --- --- - - - - - --- - -- ---- -- --- - -- -- - --- ------- - -- --- -- - ------- - - - - - - - -- ----- - - - - - -- - - - -- - - -- -- ---- -- -- -- -- - --- -- - -- - --- - ------ - - ---- -- -- - ----- - - - -- -- - -- - - ----- - -- - --- - --- - - - - -- -- --- - - - -- - --- --- --- - ---- - - - ---- - ---- -- - - -- - -- -- - -- ---- - - - - - - --- --- - - - - --- - -- -- - --- - --- -- - ---- ------- -- --- --- - - -- - - - - - -- - - ---- -- -- --- -- --- - - - --- - -- - -- --- - --- -- - - ---- - - - --- - - -- ---- --- - -- -- -- -- -- --- --- - - -- -- --- --- ---- -- -- ----- - -- - - -- ----- - -----

3 comentarios

A = randi([0 1], 5, 5)
A = 5×5
1 1 0 0 0 1 0 1 1 1 1 1 1 0 0 1 0 0 1 0 0 0 1 0 1
B = ' -';
B(A+1)
ans = 5×5 char array
'-- ' '- ---' '--- ' '- - ' ' - -'
How clever! I'm suprised that that works. I would have never thought to index into a 1x2 array with a larger index array.
The size of the index array doesn't matter for linear indexing. What matters are the values in that array.

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Patrick Laux
Patrick Laux el 20 de Mayo de 2022
excellent already, but actually I thought about having a real figure with xaxis and yaxis. Sorry that I was not very clear here.

1 comentario

A = randi([0 1], 5, 5)
A = 5×5
1 0 0 1 1 1 1 1 1 1 1 0 1 0 1 0 1 1 1 0 0 1 0 1 1
spy(A)
If you really want dashes:
figure
spy(A, '_')

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DGM
DGM el 20 de Mayo de 2022
Editada: DGM el 20 de Mayo de 2022
In the spirit of ridiculousness, here is my attempt:
% random binary data
data = randi([0 1],10,10)
data =
1 1 0 0 1 1 1 1 0 0
0 0 0 1 0 1 1 1 1 1
0 0 0 1 1 0 0 0 1 0
1 1 1 1 0 1 0 0 1 0
0 1 0 1 0 1 1 0 1 1
0 1 0 1 0 0 1 1 1 0
0 0 1 0 1 0 1 0 0 0
0 0 0 0 0 1 1 0 0 1
1 0 0 0 1 1 0 1 0 1
0 1 1 0 0 1 0 1 0 1
% convert to char data (space and full-width crossbar)
charmap = char([32 196]);
chardata = charmap(data+1)
chardata =
10×10 char array
'ÄÄ ÄÄÄÄ '
' Ä ÄÄÄÄÄ'
' ÄÄ Ä '
'ÄÄÄÄ Ä Ä '
' Ä Ä ÄÄ ÄÄ'
' Ä Ä ÄÄÄ '
' Ä Ä Ä '
' ÄÄ Ä'
'Ä ÄÄ Ä Ä'
' ÄÄ Ä Ä Ä'
% construct an image by flowing char glyphs into a rectangular box
charsize = [8 8]; % depends on the selected font
datasize = size(chardata);
tsize = [NaN datasize(2)*charsize(2)+charsize(2)/2];
outpict = textblock(chardata(:)',tsize,'font','compaq-8x8','tightwidth',true,'hardbreak',true);
% display the image with character-centered tickmarks
xrange = 0.5:datasize(1)+0.5;
yrange = 0.5:datasize(2)+0.5;
imagesc(xrange,yrange,1-outpict)
colormap(gray)
Alternatively, instead of using a full crossbar, you can just use
charmap = ' -';
and get
Bear in mind those are different random data. The point is that the bars don't touch.
This uses a few tools from MIMT, namely textblock() and imstacker().
Patrick Laux
Patrick Laux el 21 de Mayo de 2022
great answers! Thank you very much, very helpful
Voss
Voss el 21 de Mayo de 2022
Editada: Voss el 21 de Mayo de 2022
data = randi([0 1],10,30)
data = 10×30
0 0 1 1 0 1 1 1 1 0 1 0 1 0 0 1 1 1 0 1 1 1 1 1 0 1 1 0 0 0 0 1 1 0 1 0 1 1 1 1 1 0 0 1 1 0 0 1 0 1 1 1 1 0 1 0 0 0 1 0 1 1 1 1 0 1 1 0 0 0 0 0 1 1 0 1 1 0 0 1 0 1 0 0 1 0 0 1 1 1 0 1 1 0 1 0 0 1 0 0 0 0 1 1 0 1 0 1 0 0 0 1 1 1 1 1 1 0 0 1 0 1 0 1 0 1 0 1 0 1 1 0 0 1 1 1 0 1 1 1 1 0 0 1 0 1 0 0 0 1 0 1 1 0 0 0 1 1 1 1 0 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 1 1 1 0 0 0 0 1 1 0 1 1 0 0 0 0 0 0 0 0 0 1 1 1 0 1 1 0 1 0 0 0 1 1 0 1 0 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 1 1 0 0 0 0 0 0 0 1 0 1 0 1 0 1 1 0 0 0 0 0 1 1 0 1 0 0 0 1 1 1 0 1 1 0 1 1 0 1 1 1 1 1 0 0 0 1 0 1 1 0 1 1 0 0 1 1 1 0 0 0 0 1 0 1 0 0 1 1 0 1
imshow(1-data)

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Preguntada:

el 20 de Mayo de 2022

Editada:

el 21 de Mayo de 2022

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