How do I assign a 1x 50 cell array to a struct Scalar structure required for this assignment

I have a 1 x 50 cell array, which I know is scalar.

I have a 50 x 1 struct with 8 fields, which I know is not scalar isscalar(Files_struct) = 0.

I want to assign the cell array to a new field in the struct, but am getting "Scalar structure required for this assignment."

I am not finding the right documentation to answer the question. I am thinking this is simple though.

Thanks!

[Image Analyst]

A simple for loop should do it.

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[Jan]

"I have a 1 x 50 cell array, which I know is scalar." - No, a scalar cell array has the dimension 1x1.

"I want to assign the cell array to a new field in the struct" - In which struct? You have mentioned a struct array. It is easy to assign a value to a new field of a specific struct. The error message sounds, like you have tried to assign the field to the complete struct array instead. This would become clear immediately, if you show the corresponing command. It is hard to guess, what the exact problem is, if the readers have to guess, what the code is. In addition you did not mention the purpose of the code: Do you want to assign the cell array to all fields of all elements of the struct array, or to a specific one?

a = struct('field1', {1, 2, 3, 4});  % A [1 x 4] struct array
a.field2 = cell(1, 50);     % FAILING!
a(1).field2 = cell(1, 50);  % Working

Please post some code, which reproduces the problem and explain, what the code should do.

Answer 1

[Paul]

Hi Ted,

Assuming you want to assign the scalar content of each cell in the cell array a new field in the struct, is this what you're looking for?

Create an example 1x2 cell array

c = mat2cell(rand(1,2),1,[1 1])

c = 1×2 cell array
    {[0.4420]}    {[0.7149]}

Create an exampls 2x1 struct array.

s(1).field1 = 1;
s(2).field1 = 2;
s = s(:)

s = 2×1 struct array with fields:
    field1

Use deal to fill in a new field in the struct array

[s.fieldc] = deal(c{:})

s = 2×1 struct array with fields:
    field1
    fieldc

s.fieldc

ans = 0.4420

ans = 0.7149

Answer 2

[Voss]

S = struct('field1',{1;2;3},'field2',{4;5;6}); % 3-by-1 struct array
S(1), S(2), S(3)                               % show each element of the struct array

ans = struct with fields:
    field1: 1
    field2: 4

ans = struct with fields:
    field1: 2
    field2: 5

ans = struct with fields:
    field1: 3
    field2: 6

C = {'one' 'two' 'three'} % 1-by-3 cell array

C = 1×3 cell array
    {'one'}    {'two'}    {'three'}

[S.field3] = C{:}; % assign the contents of the cell array to a new field of the struct array
S(1), S(2), S(3)   % check the result

ans = struct with fields:
    field1: 1
    field2: 4
    field3: 'one'

ans = struct with fields:
    field1: 2
    field2: 5
    field3: 'two'

ans = struct with fields:
    field1: 3
    field2: 6
    field3: 'three'