How do I read data from just first row of the cell

185 views (last 30 days)
Bajdar Nour on 17 Aug 2018
this is the 3x50 cell
madhan ravi on 17 Aug 2018
Thank you sir @ Image analyst

Image Analyst on 17 Aug 2018
Bajdar, just specify 1 for the first index of the cell array feature_vec.
array17 = feature_vec{1, 7} % Get array contained in row 1, column 7 of the cell array.
If you want all the arrays in all the cells of row 1, then you can do:
row1 = feature_vec(1,:) % row1 is another cell array - a row vector cell array.
Here row1 is a cell array that is a row vector of 50 cells. Each of those 50 cells contains a double array. To get any particular array in a specified column, use braces. For example to get the cell in the 8th column, do
cellContents18 = row1{8}; % Contents of the 8th cell will be a double array.
If you don't understand when to use braces (to refer to contents of the cell) and parentheses (to refer to the cells themselves), then see <https://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F the FAQ on cell arrays.) Don't worry - granted, it's a very tricky and confusing thing that is hard for a lot of people to grasp.
Image Analyst on 20 Aug 2018
I don't see any reason to save/store all the images. Why are you doing that? Just process them in the loop and be done with that image.

Yuvaraj Venkataswamy on 17 Aug 2018
Edited: Yuvaraj Venkataswamy on 17 Aug 2018
if true
feature_vec{1,:}
end
Yuvaraj Venkataswamy on 20 Aug 2018
You are welcome

Adusumilli Bala Surendra on 24 Apr 2019
z =
1×3 cell array
{3×3 double} {3×3 double} {3×3 double}
>> z{1}
ans =
0.00315 + 0.011925i 0.0008042 + 0.0071843i 0.0008042 + 0.0061306i
0.0008042 + 0.0071843i 0.00315 + 0.011925i 0.0008042 + 0.0065829i
0.0008042 + 0.0061306i 0.0008042 + 0.0065829i 0.00315 + 0.011925i
>> z{1}(1,:)
ans =
0.00315 + 0.011925i 0.0008042 + 0.0071843i 0.0008042 + 0.0061306i