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# Write a function called halfsum that takes as input an at most two-dimensional array A and computes the sum of the elements of A that are in the lower right triangular part of A

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Will Gotcher on 7 Sep 2016
Closed: Image Analyst on 13 Jun 2020
Write a function called halfsum that takes as input an at most two-dimensional array A and computes the sum of the elements of A that are in the lower right triangular part of A, that is, elements in the counter-diagonal (going from the bottom left corner, up and to the right) and elements that are to the right of it. For example, if the input is [1 2 3; 4 5 6; 7 8 9], then the function would return 38.
This is all I have so far:
function sum=halfsum(v)
sum=0;
[row col]=size(v);
for i= 1:row;
for j=1:col;
I have spent hours on trying to figure out how to sum the reverse diagonal starting at the bottom left element and everything to the right of it and cannot seem to figure it out. Any help is greatly appreciated!
Image Analyst on 13 Jun 2020
Do not post up here. If you think that none of the 18 answers below and 2 answers above answer the question and that your answer offers something unique, then you can reopen the question to post your answer that is different than the prior 20 solutions.

James Tursa on 7 Sep 2016
Edited: James Tursa on 7 Sep 2016
Ask yourself, "what does it mean to be in the lower right triangle" in terms of i and j? I.e., what test could you make on i and j to determine if you were in the lower right triangle? Then code that up inside your for loops. E.g.,
mysum = 0; % <-- Changed sum to mysum since sum is the name of a MATLAB function
[row,col] = size(v);
for i= 1:row
for j=1:col
if( in lower right triangle ) % <-- you put test code inside parentheses
mysum = mysum + v(i,j);
end
end
end
So, you just need to figure out a test you can make on i and j to determine if you are in the lower right triangle, and insert that code inside the parentheses as noted above. If you can't figure this out immediately, write down all of the i,j pairs for a small matrix on a piece of paper and then look for a pattern that you can exploit and code up that isolates the lower right triangle. Do an example for both a square and non-square matrix to make sure the code you come up with works in both cases.
SIDE NOTE: There are ways to do this without a double for loop, but you should first learn how to do this with for loops.
##### 2 CommentsShow 1 older commentHide 1 older comment
Image Analyst on 21 Sep 2016
Uh Will, you could use my code. Did you even see it or try it??? It only accesses elements in the lower right triangle.

Vikrant Prasad on 22 Mar 2019
function summa = halfsum(A)
[row, col]=size(A);
sum=0;
for i=1:row
for j=i:col
if i<=j
sum= sum + A(i,j);
end
end
end
summa =sum;
end
mayank ghugretkar on 10 Jun 2019
another similar way
1. with for loop
function summa=halfsum(A)
[row col]=size(A);
summa=0;
j=0;
for i=1:row
for j=1:col
if j>=i
summa= A(i,j) +summa;
end
end
end
end
2. with While loop
function summa=halfsum(A)
[row col]=size(A);
summa=0;
for i=1:row
j=i;
while (j>=i && j<=col)
summa= A(i,j)+ summa;
j=j+1;
end
end
summa;
end
i love trying this things... simplifying n solving

function u = halfsum(P)
u1 = P(end:-1:1, 1:end);
u2 = triu(u1);
u = sum(u2(:));
end
Mukti Awad on 16 Aug 2019
I am getiing this error!!!
Assessment result: incorrect[1 2 3; 4 5 6; 7 8 9]
Variable summa has an incorrect value.

function summa=halfsum(m)
summa=0
[r c]=size(m)
for i=1:r
for j=1:c
if i<=j
summa=summa+m(i,j)
end
end
end

Image Analyst on 7 Sep 2016
Try
theSum = 0; % DON'T USE sum as a variable name!!!
[rows, columns] = size(v);
for row = 1 : rows
for col = (columns - row + 1) : columns
theSum = theSum + .......

Justin Whetten on 13 Dec 2016
For anyone who might be struggling still with this
function sum=halfsum(A);
sum = 0;
[row,col] = size(A);
for i= 1:row
for j=1:col
if (i+j)>=(row+1)
sum = sum + A(i,j);
end
end
end
##### 2 CommentsShow 1 older commentHide 1 older comment
Image Analyst on 14 Dec 2016
And of course, NEVER use "sum" as the name of your variable (as I mentioned in my answer) since that's the name of a very important built-in function that you won't be able to use anymore if you redefine "sum" to be your own personal variable.
And if you're puzzled by what Steve said, just see my answer.

MANAV MALHOTRA on 25 Jun 2019
function summa=halfsum(m)
summa=0;
for i=1:size(m,1)
for j=1:size(m,2)
if(i<=j)
summa=summa+sum(m(i,j));
end
end
end
for those who are less familiar with matlab

Roshan Singh on 15 Sep 2019
function summa=halfsum(a)
[r,c]=size(a);
summa=0;
for x=1:r
for y=1:c
if (x==y)||(x<y)
summa=a(x,y)+summa;
end
end
end
fprintf('summation of right hand matrix is...%d\n',summa)
end
Walter Roberson on 15 Sep 2019
(x==y)||(x<y) is the same logical condition as x<=y but x<=y is more efficient.

Sebastián Añazco on 21 Sep 2019
function summa = halfsum(A)
summa = 0;
for n = 1 : size (A,1)
for m = 1:size(A,2)
if n >m
a = 0;
else
a = A(n, m);
end
summa = summa +a;
end
end

Shubham Pandey on 3 Apr 2020
function sum = halfsum(a)
sum = 0;
[row,col] = size(a);
for i=1:row
for j=1:col
if i<=j
sum=sum+a(i,j);
end
end
end
end
Shubham Pandey on 3 Apr 2020
I agree with your feedback. Just a noobie mistake.

Nitin Kumar soni on 27 Apr 2020
function summa=halfsum(n)
[row,col]=size(n);
summa=0;
for i=1:row
for j=1:col
if i<=j
summa=summa+n(i,j);
end
end
end
Walter Roberson on 28 Apr 2020
You can avoid the if statement if you have j end at i instead of continuing to col.

Ashay Nagdive on 1 May 2020
function a = halfsum(A)
[row col]= size(A);
a = 0;
for r= 1: row
for c= 1: col
if c >= r
a= a + A(r,c)
else
A(r,c)= 0;
end
end
end

SANTOSH KAMBLE on 4 May 2020
function summa=halfsum(x)
[row col]=size(x);
summa=0;
for r=1:row
for c=1:col
y=x(r,c);
if r<=c
summa=summa+y;
end
end
end
end

ADARSH VISAJI on 9 May 2020
function summa = halfsum(A)
[row, col]=size(A);
sum=0;
for i=1:row
for j=i:col
if i<=j
sum= sum + A(i,j);
end
end
end
summa =sum;
end
if u guys have any dobts on matlab problem u can contact me through instagram
Image Analyst on 9 May 2020
This is similar to most of the other answers however you used the function name "sum" as a variable. It is not recommended to overwrite built-in functions with variables because then you can never use the built in function name anymore within that scope. For example if you wanted to do
theSum = sum(1:100);
you would not be able to because you made sum a scalar number -- it's not the built-in function anymore.

Taif Ahmed BIpul on 15 May 2020
function summa=halfsum(A)
[m,n]=size(A);
summ=0;
for i=1:m
for ii=i:n
summ=summ+A(i,ii);
end
end
summa=summ;

vighnesh rana on 19 May 2020
function summa = halfsum(A)
[row col] = size(A);
total = 0;
for r = 1:row
for c= r:col
total = total + A(r,c);
end
end
summa = total;
end

Geetanjali Alle on 5 Jun 2020
function summa = halfsum(M)
[row column]=size(M);
summa=0;
for i=1:row
for j=1:column
if i<j||i==j
summa=summa + sum(M(i,j));
end
end
end
Hope this helps!
Walter Roberson on 8 Jun 2020
i<j||i==j
would be more efficient as
i<=j
There is also an easy change to prevent you from needing the if at all.
sum(M(i,j))
M(i,j) is a scalar. sum() of a scalar is the same scalar. You do not need sum() there.

AYUSH MISHRA on 11 Jun 2020
function summa=halfsum(A)
[m,n]=size(A);
summa=0;
for i =1:m
fprintf('active row :%d \n',i);
for j=1:n
fprintf('active collumn :%d \n',j);
if m<=n
summa=summa+A(i,j);
end
fprintf('summa aeter every loop complition : %d \n',summa);
end
end
run it and understand every step working in loop